I think the problem is a bit more complicated. Not only the size ( actually surface area ) of the container but also the volume of the printed object as this reduces the volume therefore the thickness of the resin. My understanding is
- peachy hangs above a container that has a layer of resin that will float above salt water
- the laser hardens the resin wherever it shines
- salt water is 'dripped' into the container at a constant rate and raises the resin so the next layer of the object can be drawn/printed
- by counting the drops, and knowing the volume of each drop and size of container, the current height of the resin can be calculated
Setup:
1. I want to print a solid sphere of volume 10 cubic cm, ie. 100ml
2. My container has surface area of 100 sq cm
3. I pour 110ml of resin in container, so the resin is 1.1cm thick
4. As the print progresses the thickness of the resin layer reduces, halfway it is only 0.6cm thick and towards the end it is only 0.1cm
Question:
a. How do you envisage calibrating the system for the increase in Z-axis by each drop
b. How much of the initial 1.1cm depth of the resin does the laser harden
c. Does the thickness of the hardened layer reduce as the resin is consumed?
d. How do you compensate for the usage of the resin during printing?