Quote Originally Posted by LambdaFF View Post
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I think it would be great if you could just, you know, open the Cura Manual or read a bit about print prep.

The total shell thickness is linked to 2 parameters (in FDM printing) : the diameter of the printer nozzle and the number of shell-paths. Say you have a 0,4mm diam nozzle, you print at 0,45mm width and you decide to have 3 shells : total 1,35mm. It is the max external paths thickness on any horizontal slice (layer).

The infill % is basically for any slice of your part the % of surface that is filled vs the total available surface.

If at that point you're wondering why I said slice in the above sentence, please follow advice number one and find some data on slicers.

The software also allows you to decide how many layers are completely filled at the bottom and top. This is how you get to decide the shells on the vertical axis.

Now, as you can see, you set a discreete number, there is no scaling. This is not part of the design either, this is set in the print prep software, generally called slicer.

If I read you correctly, you intend to do a 1,5mm thick support ? I'm sorry but seriously, I don't need to open a Finite Element model to tell you that it won't sustain the weight of a 1kg Surface, unless you just want to use it as a shim ? Even an aluminium sheet would probably bend noticeably.

I may err on the side of over-engineering but give considerations to the dimensions I gave you. Unless of course, you just want to raise the tablet, not actually support it ?
I must remind you once again that I do not have my own printer. I will be using a printing service. I do not have the technical expertise to even begin to know how to do it myself. Most of what you have said about shells and infills and slicers is like a foreign language to me. Furthermore, none of the printing services I have checked will let me fine-tune things the way you are describing them.


The 1.5 mm support I was describing was apparently not at all what you were referring to. What I do know is that in the case of aluminum, I have a laptop tray as a reference point. It is able to support well over 5 pounds and it appears to be less than an 1/8 inch. Instead of four rectangular empty spaces, it has circular cutouts, but it's mostly the same amount of surface area as the design image I shared. This is only for reference. I know that nylon would not be as strong, but if I had some idea of the differences in specific strength between the two materials, I would be closer to understanding if my idea would work.